38 lines
1.3 KiB
38 lines
1.3 KiB
#!/usr/bin/python
|
|
# Copyright (c) 2016 PaddlePaddle Authors. All Rights Reserved
|
|
#
|
|
# Licensed under the Apache License, Version 2.0 (the "License");
|
|
# you may not use this file except in compliance with the License.
|
|
# You may obtain a copy of the License at
|
|
#
|
|
# http://www.apache.org/licenses/LICENSE-2.0
|
|
#
|
|
# Unless required by applicable law or agreed to in writing, software
|
|
# distributed under the License is distributed on an "AS IS" BASIS,
|
|
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
|
|
# See the License for the specific language governing permissions and
|
|
# limitations under the License.
|
|
import sys
|
|
import re
|
|
import math
|
|
|
|
|
|
def get_best_pass(log_filename):
|
|
with open(log_filename, 'r') as f:
|
|
text = f.read()
|
|
pattern = re.compile('Test.*? cost=([0-9]+\.[0-9]+).*?pass-([0-9]+)',
|
|
re.S)
|
|
results = re.findall(pattern, text)
|
|
sorted_results = sorted(results, key=lambda result: float(result[0]))
|
|
return sorted_results[0]
|
|
|
|
|
|
log_filename = sys.argv[1]
|
|
log = get_best_pass(log_filename)
|
|
predict_error = math.sqrt(float(log[0])) / 2
|
|
print 'Best pass is %s, error is %s, which means predict get error as %f' % (
|
|
log[1], log[0], predict_error)
|
|
|
|
evaluate_pass = "output/pass-%s" % log[1]
|
|
print "evaluating from pass %s" % evaluate_pass
|